การส่งข้อมูลแบบ post ของ jQuery พัฒนาโดยใช้ MVC Pattern

public ActionResult Index()
        {
            return View(db.Positions.ToList());
        }

        //
        // POST: /Position

        [HttpPost]
        public ActionResult Index(int id, string posName)
        {
            //Position positions = new Position();
            var positionNameQuery =
                from pos in db.Positions
                where pos.posID == id
                select pos;

            foreach (var position in positionNameQuery)
            {
                if (position.posID == id)
                {
                    position.posName = posName.ToString();
                }
            }
            db.SaveChanges();
            return View(db.Positions.ToList());
        }

<script type="text/javascript">
          function ShowEdit(par) {
              $("#divPosID-" + par).attr("class", "invisible");
              $("#txtEditPos-" + par).attr("class", "show");
              $("#btnEdit-" + par).attr("class", "hide");
              $("#btnSave-" + par).attr("class", "show");
          }
          function SaveEdit(par) {
              $("#divPosID-" + par).attr("class", "show");
              $("#txtEditPos-" + par).attr("class", "invisible");
              $("#btnEdit-" + par).attr("class", "show");
              $("#btnSave-" + par).attr("class", "hide");

              var _posName = $("#txtEditPos-" + par).val();
              var url = '@Url.Action("Index","Position")';
              $.post(url, { id: par, posName: _posName }, function (data) {
                  $("#divResult").html(data);
              });
          }
      </script>