สอบถาม xml+javascript +url จากที่อื่น ผมจะนำ xml จาก url ที่อื่นมาแสดงครับ แต่ไม่ได้สักที

$doc = new DOMDocument('1.0', 'window-874');
$doc->load('http://www.manager.co.th/RSS/Home/Breakingnews.xml');

$root = $doc->getElementsByTagName('channel'); 

foreach($root as $node)
{
	$item = $node->getElementsByTagName('item');
	foreach($item as $nodeitems)
	{
		$title = $nodeitems->getElementsByTagName('title');
		foreach($title as $titles)
		{
			echo '<br><b>'.$titles->nodeValue.'</b><br>';
		}

		$link = $nodeitems->getElementsByTagName('link');
		foreach($link as $links)
		{
			echo '<a href='.$links->nodeValue.'>'.$links->nodeValue.'</a><br>';
		}

		$desc = $nodeitems->getElementsByTagName('description');
		foreach($desc as $descs)
		{
			echo $descs->nodeValue.'<br>';
		}

		$pubdate = $nodeitems->getElementsByTagName('pubDate');
		foreach($pubdate as $pubdates)
		{
			echo $pubdates->nodeValue.'<p><hr>';
		}
	}
}

<?
function WriteXML($xml)
{
	global $file;
	$file = 'test.xml';
	$fp = fopen($file, 'w+');
	fwrite($fp,$xml);
	fclose($fp);
}

function CopyXML($url)
{
	$xml = new DOMDocument("1.0","window-874");
	$xml->load($url);
	$text = $xml->SaveXML();
	WriteXML($text);
}

$xml_url = 'http://www.manager.co.th/RSS/Home/Breakingnews.xml';
CopyXML($xml_url);
echo file_get_contents($file);
?>