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                คือผมต้องากรให้ login ถ้า class เป็น admin แล้ว รีไดเร็กมาหน้า admin.php ถ้าเป็น user ให้ ไปหน้า user.php แต่ไม่ทราบว่าจะต้องเขียนยังไงช่วยทีครับ 
 
Code (PHP) 
<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN"
"http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
<title>Ajax Login in php using jquery's fading effects</title>
<meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1">
<script src="jquery.js" type="text/javascript" language="javascript"></script>
<script language="javascript">
//  Developed by Roshan Bhattarai 
//  Visit http://roshanbh.com.np for this script and more.
//  This notice MUST stay intact for legal use
$(document).ready(function()
{
	$("#login_form").submit(function()
	{
		//remove all the class add the messagebox classes and start fading
		$("#msgbox").removeClass().addClass('messagebox').text('Validating....').fadeIn(1000);
		//check the username exists or not from ajax
		$.post("ajax_login.php",{ username:$('#username').val(),password:$('#password').val(),rand:Math.random() } ,function(data)
        {
		  if(data=='yes') //if correct login detail
		  {
		  	$("#msgbox").fadeTo(200,0.1,function()  //start fading the messagebox
			{ 
			  //add message and change the class of the box and start fading
			  $(this).html('Logging in.....').addClass('messageboxok').fadeTo(900,1,
              function()
			  { 
			  	 //redirect to secure page
				 document.location='admin.php';
			  });
			  
			});
		  }
		  else 
		  {
		  	$("#msgbox").fadeTo(200,0.1,function() //start fading the messagebox
			{ 
			  //add message and change the class of the box and start fading
			  $(this).html('Your login detail sucks...').addClass('messageboxerror').fadeTo(900,1);
			});		
          }
				
        });
 		return false; //not to post the  form physically
	});
	//now call the ajax also focus move from 
	$("#password").blur(function()
	{
		$("#login_form").trigger('submit');
	});
});
</script>
<style type="text/css">
body {
font-family:Verdana, Arial, Helvetica, sans-serif;
font-size:11px;
}
.top {
margin-bottom: 15px;
}
.buttondiv {
margin-top: 10px;
}
.messagebox{
	position:absolute;
	width:100px;
	margin-left:30px;
	border:1px solid #c93;
	background:#ffc;
	padding:3px;
}
.messageboxok{
	position:absolute;
	width:auto;
	margin-left:30px;
	border:1px solid #349534;
	background:#C9FFCA;
	padding:3px;
	font-weight:bold;
	color:#008000;
	
}
.messageboxerror{
	position:absolute;
	width:auto;
	margin-left:30px;
	border:1px solid #CC0000;
	background:#F7CBCA;
	padding:3px;
	font-weight:bold;
	color:#CC0000;
}
</style>
</head>
<body>
 
<br>
<br>
<form method="post" action="" id="login_form">
<div align="center">
<div class="top" > A fancy ajax login usin jQuery - <strong style="color:#FF0000">Use "admin" as username and "roshan" as password </strong></div>
<div >
   User Name : <input name="username" type="text" id="username" value="" maxlength="20" />
</div>
<div style="margin-top:5px" >
   Password :
      
    <input name="password" type="password" id="password" value="" maxlength="20" />
   
</div>
<div class="buttondiv">
    <input name="Submit" type="submit" id="submit" value="Login" style="margin-left:-10px; height:23px"  /> <span id="msgbox" style="display:none"></span>
   
</div>
</div>
</form>
</body>
</html>
 
 
อันนี้เป็น ajax_login.php 
 
Code (PHP) 
<?php session_start();
//  Developed by Roshan Bhattarai 
//  Visit http://roshanbh.com.np for this script and more.
//  This notice MUST stay intact for legal use
//Connect to database from here
$link = mysql_connect('localhost', 'quickmanag_data', 'admin'); 
if (!$link) {
    die('Could not connect: ' . mysql_error());
}
//select the database | Change the name of database from here
mysql_select_db('test'); 
//get the posted values
$user_name=htmlspecialchars($_POST['username'],ENT_QUOTES);
$pass=md5($_POST['password']);
//now validating the username and password
$sql="SELECT username, password FROM user WHERE username='".$user_name."'";
$result=mysql_query($sql);
$row=mysql_fetch_array($result);
//if username exists
if(mysql_num_rows($result)>0)
{
	//compare the password
	if(strcmp($row['password'],$pass)==0)
	{
		echo "yes";
		//now set the session from here if needed
		$_SESSION['u_name']=$user_name; 
	}
	else
		echo "no"; 
}
else
	echo "no"; //Invalid Login
?>
 
 
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                      | Date :
                          2010-06-10 18:32:23 | 
                      By :
                          7thStyle | 
                      View :
                          1340 | 
                      Reply :
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