รบกวนคนเก่ง AJAX กับ JAVA ช่วยหน่อยครับ โค๊ต Ajax ของผมเป็นแบบนี้

function ajaxLoad(method, URL, data, displayId) {
	
	var ajax = null;
	if(window.ActiveXObject){
		ajax = new ActiveXObject("Microsoft.XMLHTTP");		
	}
	else if(window.XMLHttpRequest){
		ajax = new XMLHttpRequest();		
	}
	else{
		alert("Your browser doesn't support Ajax");
		return;
	}
	
	method = method.toLowerCase();
	URL += "?dummy=" + (new Date()).getTime();
	if(method.toLowerCase() == "get") {		
		URL += "&" + data;
		data = null;
	}
	ajax.open(method, URL);
	if(method.toLowerCase() == "post"){
		ajax.setRequestHeader("Content-Type","application/x-www-form-urlencoded");
	}
	ajax.onreadystatechange = function() {
			
		if(ajax.readyState==4 && ajax.status==200){
			var ctype = ajax.getResponseHeader("Content-Type");
			ctype = ctype.toLowerCase();			
			
			if(ctype.match("text/plain")){
				ajaxCallback(ctype, displayId, ajax.responseText);				
			}			
			else if(ctype.match("text/javascript")){
				eval(ajax.responseText);
			}
			delete ajax;
			ajax = null;
		}
	}
	ajax.send(data);
}

function ajaxCallback(contentType, displayId, responseText){
	if(contentType.match("text/javascript")){
		eval(responseText);
	}
	else {
		var el = document.getElementById(displayId);
		el.innerHTML = responseText;
	}
}

function SendMail(){		
		var idQ =  document.getElementById("idQ").value;
		var mailcus =  document.getElementById("mailcus").value;
		var mailcus2 =  document.getElementById("mailcus2").value;
		var mailother =  document.getElementById("mailother").value;
		var mailother2 =  document.getElementById("mailother2").value;		

		var data = "stap2=yes&mailcus=" + mailcus + "&mailcus2=" + mailcus2 + "&mailother=" + mailother + "&mailother2=" + mailother2 + "&idQ=" + idQ ;     		
				
		var URL = "Quotation_ajax.php";
		
		ajaxLoad("post", URL, data, "");
}