ผมไม่สามารถแสดงภาพจากฐานข้อมูล mysql ที่เป็น BLOB ไม่ได้ครับ

<?php
						$con = mysql_connect("localhost","root","1234");
						mysql_select_db("ecom");
						$charset = "SET character_set_results=UTF8"; 		
						mysql_query($charset) or die('Invalid query: ' . mysql_error()); 
						$result = mysql_query("select * from news order by num asc");
						while($row=mysql_fetch_array($result))
						{	
								$num = $row['num'];
								$pic = $row['pic'];
								$data = $row['data'];	
								print"<td width='200' height='130' valign='middle'><img src ='show_pic.php?num = ".$num."'></td>";
								print"<td width='10' height='130' valign='middle' ></td>";
								print"<td width='290'  height='130' valign='middle' >".$data."</td>";
								print"</tr>";      
						}
						mysql_close($con);		
						?>  

<?

	$con = mysql_connect("localhost","root","1234") or die("ติดต่อฐานข้อมูลไม่ได้");
	mysql_select_db("ecom") or die("เลือกฐานข้อมูลไม่ได้");
	$charset = "SET character_set_results=UTF8"; 
	mysql_query($charset) or die('Invalid query: ' . mysql_error());
 	$num = $_GET["num"];
	$result = mysql_query("select * from news where num = ".$num."");

	while($row=mysql_fetch_array($result))
	
	{
		$pic = $row['pic'];
		
	}
header('Content-Length: '.strlen($pic));
header("Content-type: image/{jpeg}");
		
	mysql_close($con);
	
?>