ช่วยดู warning หน่อยครับว่า มันผิดยังไง ต้องแก้ไขตรงไหน ... Warning: mysql_fetch_array(): supplied argument is not a valid MySQL result resource in

include('config.php');
if(isset($search) ) {
echo "<font size='-1' color='#FF0000'>ผลลัพธ์ของคำว่า [ $search ] </font><br />";

$result = mysql_query("SELECT * FROM m01 where title like '%$search%'" );
$num = mysql_num_rows($result);
echo "ค้นพบทั้งหมด :: [ $num ] </font><br />";

$sql = "select * from m01 where title like %$search% ";
$view = mysql_query($sql);

while ($data = mysql_fetch_array($view) ) 
{
[font=Verdana]$result = mysql_fetch_array($dbquery);  << 34 ผิด ยังไงครับ[/font]

$id = $data[id];
$title = $data[title];
$R1 = $data[R1];
$R2 = $data[R2];
$R3 = $data[R3];
$mon = $data[mon];