ผม query ข้อมูลจากไฟล์ php เป็น JSON ช่วยเขียนโค้ด รับและปักหมุด google map ให้หน่อย ครับ

				$objConnect = mysql_connect("localhost","root","") or die(mysql_error());
				$objDB = mysql_select_db("mydatabase");
				$strSQL = "SELECT * FROM customer WHERE 1 AND CountryCode like '%".$strCountry."%' ";
				$objQuery = mysql_query($strSQL) or die (mysql_error());
				$intNumField = mysql_num_fields($objQuery);
				$resultArray = array();
				while($obResult = mysql_fetch_array($objQuery))
				{
					$arrCol = array();
					for($i=0;$i<$intNumField;$i++)
					{
						$arrCol[mysql_field_name($objQuery,$i)] = $obResult[$i];
					}
					array_push($resultArray,$arrCol);
				}
				
				echo json_encode($resultArray);

<script type="text/javascript">
$(document).ready(function(){

	$("#btn1").click(function(){
			$.ajax({ 
				url: "WebServiceClient.php" ,
				type: "POST",
				data: 'keyword=' +$("#txtCountryCode").val()
			})
			.success(function(result) { 

					$("#div1").empty();

				var obj = jQuery.parseJSON(result);
				  $.each(obj, function(key, val) {

					   $("#div1").append('<hr />');
					   $("#div1").append('[' + key + '] ' + 'CustomerID=' + val["CustomerID"] +'<br />');
					   $("#div1").append('[' + key + '] ' + 'Name=' + val["Name"] +'<br />');
					   $("#div1").append('[' + key + '] ' + 'Email=' + val["Email"] +'<br />');
					   $("#div1").append('[' + key + '] ' + 'CountryCode=' + val["CountryCode"] +'<br />');
					   $("#div1").append('[' + key + '] ' + 'Budget=' + val["Budget"] +'<br />');
					   $("#div1").append('[' + key + '] ' + 'Used=' + val["Used"] +'<br />');

				  });

			});

		});
	});
</script>