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[PHP] [Ajax] จาก code ตัวอย่างจะทำเป็น function แล้วเก็บไว้เรียกใช้หลายๆ หน้าได้อย่างไรครับ |
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จะได้ลดการเขียน code ลงครับ
จาก link นี้ครับ
https://www.thaicreate.com/tutorial/ajax-list-record-paging.html
AjaxPHPListRecordPaging1.php
<?php
/*** By Weerachai Nukitram***/
/*** http://www.ThaiCreate.Com ***/
?>
<html>
<head>
<title>ThaiCreate.Com Ajax Tutorial</title>
</head>
<script language="JavaScript">
var HttPRequest = false;
function doCallAjax(Page) {
HttPRequest = false;
if (window.XMLHttpRequest) { // Mozilla, Safari,...
HttPRequest = new XMLHttpRequest();
if (HttPRequest.overrideMimeType) {
HttPRequest.overrideMimeType('text/html');
}
} else if (window.ActiveXObject) { // IE
try {
HttPRequest = new ActiveXObject("Msxml2.XMLHTTP");
} catch (e) {
try {
HttPRequest = new ActiveXObject("Microsoft.XMLHTTP");
} catch (e) {}
}
}
if (!HttPRequest) {
alert('Cannot create XMLHTTP instance');
return false;
}
var url = 'AjaxPHPListRecordPaging2.php';
var pmeters = 'myPage='+Page;
HttPRequest.open('POST',url,true);
HttPRequest.setRequestHeader("Content-type", "application/x-www-form-urlencoded");
HttPRequest.setRequestHeader("Content-length", pmeters.length);
HttPRequest.setRequestHeader("Connection", "close");
HttPRequest.send(pmeters);
HttPRequest.onreadystatechange = function()
{
if(HttPRequest.readyState == 3) // Loading Request
{
document.getElementById("mySpan").innerHTML = "Now is Loading...";
}
if(HttPRequest.readyState == 4) // Return Request
{
document.getElementById("mySpan").innerHTML = HttPRequest.responseText;
}
}
}
</script>
<body Onload="JavaScript:doCallAjax('1');">
<h1>My Customer</h1>
<span id="mySpan"></span>
</body>
</html>
AjaxPHPListRecordPaging2.php
<?php
/*** By Weerachai Nukitram ***/
/*** http://www.ThaiCreate.Com ***/
$strPage = $_POST["myPage"];
$objConnect = mysql_connect("localhost","root","root") or die("Error Connect to Database");
$objDB = mysql_select_db("mydatabase");
$strSQL = "SELECT * FROM customer ";
$objQuery = mysql_query($strSQL) or die ("Error Query [".$strSQL."]");
$Num_Rows = mysql_num_rows($objQuery);
$Per_Page = 2; // Per Page
$Page = $strPage;
if(!$strPage)
{
$Page=1;
}
$Prev_Page = $Page-1;
$Next_Page = $Page+1;
$Page_Start = (($Per_Page*$Page)-$Per_Page);
if($Num_Rows<=$Per_Page)
{
$Num_Pages =1;
}
else if(($Num_Rows % $Per_Page)==0)
{
$Num_Pages =($Num_Rows/$Per_Page) ;
}
else
{
$Num_Pages =($Num_Rows/$Per_Page)+1;
$Num_Pages = (int)$Num_Pages;
}
$strSQL .=" order by CustomerID ASC LIMIT $Page_Start , $Per_Page";
$objQuery = mysql_query($strSQL);
?>
<table width="600" border="1">
<tr>
<th width="91"> <div align="center">CustomerID </div></th>
<th width="98"> <div align="center">Name </div></th>
<th width="198"> <div align="center">Email </div></th>
<th width="97"> <div align="center">CountryCode </div></th>
<th width="59"> <div align="center">Budget </div></th>
<th width="71"> <div align="center">Used </div></th>
</tr>
<?
while($objResult = mysql_fetch_array($objQuery))
{
?>
<tr>
<td><div align="center"><?=$objResult["CustomerID"];?></div></td>
<td><?=$objResult["Name"];?></td>
<td><?=$objResult["Email"];?></td>
<td><div align="center"><?=$objResult["CountryCode"];?></div></td>
<td align="right"><?=$objResult["Budget"];?></td>
<td align="right"><?=$objResult["Used"];?></td>
</tr>
<?
}
?>
</table>
<br>
Total <?= $Num_Rows;?> Record : <?=$Num_Pages;?> Page :
<?
if($Prev_Page)
{
echo " <a href=\"JavaScript:doCallAjax('$Prev_Page')\"><< Back</a> ";
}
for($i=1; $i<=$Num_Pages; $i++){
if($i != $Page)
{
echo "[ <a href=\"JavaScript:doCallAjax('$i')\">$i</a> ]";
}
else
{
echo "<b> $i </b>";
}
}
if($Page!=$Num_Pages)
{
echo " <a href=\"JavaScript:doCallAjax('$Next_Page')\">Next >></a> ";
}
mysql_close($objConnect);
?>
Tag : PHP, MySQL, Ajax
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| Date :
2013-07-27 11:41:29 |
By :
zoberranger |
View :
877 |
Reply :
2 |
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include("javascript/???????.php");
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| Date :
2013-07-27 11:53:28 |
By :
teez1232002 |
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ใช้ jQuery ง่ายกกว่าน่ะครับ 
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| Date :
2013-07-27 19:17:47 |
By :
mr.win |
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 Load balance : Server 01
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