ถ้าจะทำแบบว่า ให้ลูกค้าพิมชื่อลงไปใน textbox แล้วพอตรวจสอบว่ามีชื่อนี้จิง แล้วให้ enable ปุ่ม submit แต่ท่าไม่เจอให้ disable ปุ่ม submit ทำยังไงคับ ใครพอทราบบ้าง

<form action="......" method="post">
<input type="text" name="name">
<button id="check">ตรวจสอบ</button>
<input type="submit" id="submit" value="submit">
</form>

<script>
$("#check").click(function(){
   var text = $("input[name=name]").val();

  $.ajax({
   url: "data.php",
   type: "post",
   data: {text:text},
   success: function(data){
     if(data == '1')
     {
          $("#submit").attr("disabled","true");
     }else{
         $("#submit").attr("disabled","false");
      }
}
})
})
</script>

<?php
$name = $_POST['text'];
$sql = mysql_query("SELECT * FROM member WHERE name='$name'");
$num = mysql_num_rows($sql);
if($num >= 1)
{
echo '1';
}else{
echo '0';
}
?>

$("#check").click

$("input[name=name]").blur

<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<input type="text" id="txtContent" />
<span id="sMsg">&times;</span><br />
<input type="submit" id="btn" value="Send" disabled="disabled" />
<script src="admin/bootstrap/js/jquery-1.10.2.min.js"></script>
<script>
	$(function(){
		$('#txtContent').keyup(function(){
			$.ajax({url:"check.php",
				async:false,
				cache:false,
				global:false,
				type:"POST",
				data:"Content="+$(this).val(),
				success: function(result){
					var obj=jQuery.parseJSON(result);
					if(obj['Callback']=='Same'){
						$('#sMsg').empty();
						$('#sMsg').append('&radic;');
						$('#btn').attr({'disabled':false});	
					}else{
						$('#sMsg').empty();
						$('#sMsg').append('&times;');
						$('#btn').attr({'disabled':true});
					}
				}
			});	
		});	
	});
</script>

<?php
	include ("admin/module/php/config.inc.php");
	
	$Content=$_POST['Content'];
	$select=mysql_query("SELECT * FROM active_content WHERE Content='".$Content."'") or die (mysql_error());
	$num_rows=mysql_num_rows($select);
	$arr=array();
	if($num_rows == 1){
		$arr['Callback']="Same";
	}else{
		$arr['Callback']="";
	}
	echo json_encode($arr);
?>