สอบถามการ Query ข้อมูลเพื่อออกรายงานครับ ช่วยหน่อยนะครับ อิอิ

<?
require("connect.php");
?>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<style type="text/css">
<!--
.style1 {
	font-family: "TH SarabunPSK";
	font-size: 18pt;
	font-weight: bold;
}
.style2 {
	font-family: "TH SarabunPSK";
	font-size: 16pt;
	font-weight: bold;
}
.style3 {
	font-family: "TH SarabunPSK";
	font-size: 16pt;
	
}
.style5 {cursor: hand; font-weight: normal; color: #000000;}
.style9 {font-family: Tahoma; font-size: 12px; }
.style11 {font-size: 12px}
.style13 {font-size: 9}
.style16 {font-size: 9; font-weight: bold; }
.style17 {font-size: 12px; font-weight: bold; }
-->
</style>

<table width="788" border="1" align="center" cellpadding="1" cellspacing="1" bordercolor="#000000">

  <tr>
    <td width="36" align="center" bgcolor="#CCCCCC" class="style2">ที่</td>
    <td width="469" align="center" bgcolor="#CCCCCC" class="style2">ราละเอียดงบประมาณ</td>
    <td width="137" align="center" bgcolor="#CCCCCC" class="style2">งบแผ่นดิน</td>
    <td width="123" align="center" bgcolor="#CCCCCC" class="style2">งบผลประโยชน์</td>
  </tr>
  <?php
            $sql_show  = "SELECT * FROM tbbudgetdetail";
           	$sql_show .= " LEFT JOIN tbbudgetcategory ON tbbudgetdetail.BudgetcategoryID = tbbudgetcategory.BudgetcategoryID";
			$sql_show .= " WHERE tbbudgetcategory.BudgetyearID = '".$datebg."'";
            $result_show = mysql_query($sql_show) or die(mysql_error());
            if(mysql_numrows($result_show) > 0){ // เช็คว่ามีข้อมูลหรือไม่
            while($row_show = mysql_fetch_array($result_show)) {
        ?>
  <tr class="style3">
    <td align="center" class="style2">&nbsp;</td>
    <td class="style2"><?=$row_show['Budgetdetail']; ?></td>
    
    <td>&nbsp;</td>
    <td>&nbsp;</td>
     <?php } } else { ?>
       
  </tr>
  <tr>
    <td align="center" class="style2">&nbsp;</td>
    <td class="style2">รวมทั้งสิ้น</td>
    <td>&nbsp;</td>
    <td>&nbsp;</td>
  </tr>
 
        <?php } ?>
</table>