ต้องการเรียกรูปภาพในฐานข้อมูลมาโชว์ใน list menu จะได้ไหมครับ

<?
include "dbconfig.php";
conndb();

	header("content-type: text/plain; charset=tis-620");

	$no_room = iconv("UTF-8","TIS-620",$_POST['no_room']);

if($no_room != 0){

$msg_return = <<< DATA0

      <TABLE style="MARGIN-TOP: 5px; FONT-SIZE: 11px; FONT-FAMILY: Arial, Helvetica, sans-serif" borderColor=#f2f2f2 cellSpacing=2 cellPadding=0 width="90%" bgColor=#ffffff border=0>
        <TBODY>
        <TR bgColor=#f9fbf1>
          <TD width="5%" background=images/title-bg2.png height=20>
            <DIV align=center><B>No</B></DIV></TD>
          <TD width="95%" background=images/title-bg2.png height=20>
            <DIV align=center><B>Room Type</B></DIV></TD>
        </TR>

DATA0;

for($i=0;$i<$no_room;$i++){

$no = $i + 1;

$msg_return .= <<< DATA1_1

        <TR bgColor=#ffffff>
          <TD style="PADDING-RIGHT: 2px; PADDING-LEFT: 2px; PADDING-BOTTOM: 2px; PADDING-TOP: 2px" align="center">$no</TD>
          <TD style="PADDING-RIGHT: 2px; PADDING-LEFT: 2px; PADDING-BOTTOM: 2px; PADDING-TOP: 2px"><div align="center">
               <select name="room_id[]" id="myselect" style="FONT-SIZE: 12px">";
DATA1_1;

$sql_lookup_text = "SELECT * FROM room_tb ORDER BY order_list";
$result_lookup = mysql_query($sql_lookup_text);
While($row_lookup = mysql_fetch_array($result_lookup)){
   $msg_return .= "
   <option value=\"".$row_lookup['id']."\" style=\"width: auto;\">".$row_lookup['name']."
   </option>\n";
}


$msg_return .= <<< DATA1_2
              </select>
</div>
          </TD>
        </TR>
DATA1_2;


}


$msg_return .= <<< DATA2

        </TBODY></TABLE>

DATA2;

}

echo $msg_return;

?>