upld upload script ทำอย่างไรให้แบ่งหน้าแสดงรูปภาพได้ครับ

<?php

require('config.php');
require('common.php');

if (!isset($_SESSION['user']))
{
	exit_message('You are no authorised to access this page. Please log in.');
}

$user = $_SESSION['user'];

require('db.php');

$images = mysqli_prepare($db, 'SELECT `id`, `ext`, `time` FROM `images` WHERE `removed` = "0" ORDER BY `time` desc'); //ORDER BY `time` ASC'

mysqli_stmt_bind_param($images, 'i', $user);
mysqli_stmt_execute($images);
++$db_queries;
mysqli_stmt_store_result($images);

if (mysqli_stmt_num_rows($images) === 0)
{
	exit_message('You haven\'t uploaded any images yet!');
}

mysqli_stmt_bind_result($images, $id, $ext, $time);

require('inc/header.php');
require('inc/account.php');
require('inc/footer.php');

<?php

if (!defined('IN_SCRIPT'))
{
	header('location: ../index.php');
	exit;
}

?>

<div class="box">

	<p class="title">Your account</p>

	<p>Welcome to your account. You can view all of your uploads here, see the upload time and delete them</p>

	<div id="user-images"><!--

<?php

while (mysqli_stmt_fetch($images))
{

?>

		--><div class="user-image-box">
			<a href="<?php echo VIEW_PATH . $id; ?>"><img class="user-image" src="thumbs/<?php echo $id . '.jpg'; ?>" alt="<?php echo $id; ?>" /></a>
			<ul class="image-actions">
				<li>image ID : <?php echo $id; ?></li>
				<li>uploaded <?php echo $time; ?></li>
				<li><a class="delete" href="delete.php?id=<?php echo $id; ?>">DELETE image</a></li>
			</ul>
		</div><!--

<?php

}

?>

--></div>

<?php

mysqli_stmt_close($images);
mysqli_close($db);

?>

</div>