พี่ๆแนะนำให้หน่อยค่ะ multi submenu อ่าค่ะ แก้ไม่ได้ซะที

$strquery = "SELECT A.role_id,B.page_id,C.parent_page
							FROM system_user_role_tbl AS A
							INNER JOIN system_page_role_tbl AS B
									ON A.role_id = B.role_id
									AND B.rec_status = 1
							INNER JOIN system_page_tbl AS C
									ON C.page_id = B.page_id
									AND C.rec_status=1
									AND A.user_id = '1f5443f497b7e955ffde9d83863f5868' 
									AND A.rec_status = 1
									group by B.page_id";
		
				 $result = mysql_query($strquery);
				
				 $num = mysql_num_fields($result);
				$r=0;
				
				 while($data =mysql_fetch_row($result)){
				
					$res[$r] = getmenu($data[1]);
					
					$r++;
				
				 }
				 
				 foreach($res as $value)
				 {
				 		$page = split(",",$value);
				
						if(count($page) == 1)
						{
							echo "<div style='width:100px;float:left;border:solid;'>";
							echo "<div style='padding-right:5px;'>".$page[0]."</div>";
							echo "</div>";
						}else{
							echo "<div style='width:100px;float:left;border:solid;'>";
								for($n=count($page)-1;$n>-1;$n--)
								{
									echo "<div style='padding-right:5px;''>".$page[$n]."</div>";
									
								}
							echo "</div>";
						}
				
				 	
				 }
				function getmenu($pageid){
						
						$strquery = "SELECT A.role_id,B.page_id,C.parent_page
									FROM system_user_role_tbl AS A
									INNER JOIN system_page_role_tbl AS B
											ON A.role_id = B.role_id
											AND B.rec_status = 1
									INNER JOIN system_page_tbl AS C
											ON C.page_id = B.page_id
											AND C.page_id = '".$pageid."'
											AND C.rec_status=1
											AND A.rec_status = 1
											group by B.page_id";
											
						 $result = mysql_query($strquery);
						
						
						
						 while($data =mysql_fetch_row($result)){
								
								
								if($data[2] != NULL){
									
										return $data[1].",".getmenu($data[2]);
										
								}else{
									
									return $data[1];
									
								}
						
						 }					
						
				}