 |
ช่วยดู Code PHP หน่อยคับ mysql_fetch_assoc(): supplied argument is not a valid MySQL result resource |
|
 |
|
|
 |
 |
|
....................
|
ประวัติการแก้ไข 2012-06-01 18:05:39
 |
 |
 |
 |
Date :
2012-06-01 17:53:23 |
By :
nukedonut1 |
|
 |
 |
 |
 |
|
|
 |
 |
|
 |
 |
 |
|
|
 |
 |
|
ไม่หายอ่ะคับ
|
 |
 |
 |
 |
Date :
2012-06-01 17:57:11 |
By :
nukedonut1 |
|
 |
 |
 |
 |
|
|
 |
 |
|
 |
 |
 |
|
|
 |
 |
|

Code (PHP)
<?php
function fetch_users(){
$result = mysql_query('SELECT `user_id` AS `id`, `user_username` AS `username` FROM `users`');
$users = array();
while (($row = mysql_fetch_assoc($result)) !== false){
$users[] = $row;
}
return $users;
}
function fetch_user_info($uid){
$uid = (int)$uid;
$sql = "SELECT *
`user_username` AS `username`,
`user_pwd` AS `password`,
`user_name` AS `name`,
`user_email` AS `email`,
`user_about` AS `about`,
`user_status` AS `status`
FROM `users`
WHERE `user_id = {$uid}";
$result = mysql_query($sql) or die(mysql_error());
return mysql_fetch_assoc($result);
}
?>
|
 |
 |
 |
 |
Date :
2012-06-01 18:00:38 |
By :
nukedonut1 |
|
 |
 |
 |
 |
|
|
 |
 |
|
 |
 |
 |
|
|
 |
 |
|
user_id ขาดอีกตัว
|
 |
 |
 |
 |
Date :
2012-06-01 18:18:32 |
By :
ผ่านมา |
|
 |
 |
 |
 |
|
|
 |
 |
|
 |
 |
 |
|
|
 |
 |
|
ไม่หายอ่ะคับ
|
 |
 |
 |
 |
Date :
2012-06-01 18:31:36 |
By :
nukedonut1 |
|
 |
 |
 |
 |
|
|
 |
 |
|
 |
 |
 |
|
|
 |
 |
|
Error อะไรอีกครับ
|
 |
 |
 |
 |
Date :
2012-06-01 20:47:48 |
By :
mr.win |
|
 |
 |
 |
 |
|
|
 |
 |
|
 |
 |
 |
|
|
 |
 |
|
หรือไม่ก็เอา code มาดูอีกครับ
|
 |
 |
 |
 |
Date :
2012-06-01 21:20:42 |
By :
mr.win |
|
 |
 |
 |
 |
|
|
 |
 |
|
 |
 |
|
|