ช่วยหน่อยครับ Warning: mysql_fetch_array(): supplied argument is not a valid MySQL result resource

<?
	$UserId = $_SESSION["UserId"];
	$sql = "select * from applicant where UserId = '$UserId'";
	$result = mysql_query($sql);
	$row = mysql_fetch_array($result);
	
	$ApplicantId = $row["ApplicantId"];
	
	$sql = "select * from family where ApplicantId = ApplicantId";
	$result = mysql_query($sql);
	$row = mysql_fetch_array($result);
	
	$sql = "select Level,Institution,Major,q.QuaName,Grade,Admission,Graduated from education e inner join qualification q on e.QuaId = q.QuaId";
	$result = mysql_query($sql);
	$row = mysql_fetch_array($result);
	
	$sql = "select * from experiences where ApplicantId = ApplicantId";
	$result = mysql_query($sql);
	$row = mysql_fetch_array($result);
	
	$sql = "select * from training where ApplicantId = ApplicantId";
	$result = mysql_query($sql);
	$row = mysql_fetch_array($result);
	
	$sql = "select l1.Language,SpeakLev,ListenLev,ReadLev,WriteLev from language l1 inner join langlevel l2 on l1.LandId = l2.LandId";
	$result = mysql_query($sql);
	$row = mysql_fetch_array($result);
	
	$sql = "select p1.Program,ProLev from program p1 inner join prolevel p2 on p1.ProId = p2.ProId";
	$result = mysql_query($sql);
	$row = mysql_fetch_array($result);
	
	
?>