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สอบถามปัญหาคำสั่ง SQL ของ MySQL เมื่อ ขึ้นerror : [color=red]Warning: mysqli_fetch_assoc() expects parameter 1 to be mysqli_result, array given in C:\xampp\htdocs\travel01\index.php on line 33[/color] |
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Warning: mysqli_fetch_assoc() expects parameter 1 to be mysqli_result, array given in C:\xampp\htdocs\travel01\index.php on line 33
โคดหน้าที่ error
Code
<?php
session_start();
include 'secure/connectdb.php';
$sql = "SELECT * FROM tbnew INNER JOIN tbnewtype ON tbnew.newstype_id=tbnewtype.newstype_id ORDER BY news_id DESC LIMIT 2";
$result = mysqli_query($dbcon, $sql);
?>
<!DOCTYPE html>
<html>
<head>
<meta charset="UTF-8">
<title></title>
<link rel="stylesheet" href="css/uikit.min.css" />
<script src="js/jquery.js"></script>
<script src="js/uikit.min.js"></script>
</head>
<body>
<div class="uk-container uk-container-center uk-margin-top uk-margin-large-bottom">
<div class="uk-container uk-container-center uk-margin-top uk-margin-large-bottom">
<?php
include 'header.php';
?>
<div class="uk-grid" data-uk-grid-margin>
<div class="uk-width-medium-3-4">
<?php
while ($result = mysqli_fetch_assoc($result)) {
?>
<article class="uk-article">
<h1 class="uk-article-title">
<a href="layouts_post.html"><?php echo $result['news_topic']; ?></a>
</h1>
<p class="uk-article-meta">Written by Author on 12 April 2013. Posted in <a href="#">Blog</a></p>
<p>
<a href="layouts_post.html"><img width="900" height="300" src="data:image/svg+xml;base64,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" alt=""></a>
</p>
<p>Lorem ipsum dolor sit amet, consectetur adipisici elit, sed eiusmod tempor incidunt ut labore et dolore magna aliqua. Ut enim ad minim veniam, quis nostrud exercitation ullamco laboris nisi ut aliquid ex ea commodi consequat. Quis aute iure reprehenderit in voluptate velit esse cillum dolore eu fugiat nulla pariatur. Excepteur sint obcaecat cupiditat non proident, sunt in culpa qui officia deserunt mollit anim id est laborum.</p>
<h2>Subheading</h2>
<p>Lorem ipsum dolor sit amet, consectetur adipisici elit, sed eiusmod tempor incidunt ut labore et dolore magna aliqua. Ut enim ad minim veniam, quis nostrud exercitation ullamco laboris nisi ut aliquid ex ea commodi consequat. Quis aute iure reprehenderit in voluptate velit esse cillum dolore eu fugiat nulla pariatur. Excepteur sint obcaecat cupiditat non proident, sunt in culpa qui officia deserunt mollit anim id est laborum.</p>
<p>
<a class="uk-button uk-button-primary" href="layouts_post.html">Continue Reading</a>
<a class="uk-button" href="layouts_post.html">4 Comments</a>
</p>
</article>
<?php } ?>
</div>
<?php include 'right.php'; ?>
</div> <!-- end grid -->
</div>
<?php
include 'rs.php';
?>
</body>
</html>
Tag : PHP, MySQL, HTML, HTML5, Web Services, Appserv
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| Date :
2019-03-12 00:13:19 |
By :
1541158739347519 |
View :
918 |
Reply :
3 |
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ตัวแปรที่เป็น qury
result มันซ้ำกันครับ
$sql = "SELECT * FROM tbnew INNER JOIN tbnewtype ON tbnew.newstype_id=tbnewtype.newstype_id ORDER BY news_id DESC LIMIT 2";
$result = mysqli_query($dbcon, $sql);
while ($result = mysqli_fetch_assoc($result)) {
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| Date :
2019-03-12 09:26:38 |
By :
nobetaking |
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ประวัติการแก้ไข
2019-03-12 13:24:07
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| Date :
2019-03-12 13:22:42 |
By :
1541158739347519 |
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