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เกิด error แบบนี้แก้ยังไงได้บ้างคะ Warning: mysqli_query() expects parameter 1 to be mysqli, resource given in |
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มันขึ้นแสดงตลอดเวลากดปุ่มเพื่อบันทึกลงในฐานข้อมูล
Warning: mysqli_query() expects parameter 1 to be mysqli, resource given in C:\xampp\htdocs\subconinfo\user\save_subcon.php on line 26
Warning: mysqli_query() expects parameter 1 to be mysqli, resource given in C:\xampp\htdocs\subconinfo\user\save_subcon.php on line 46
นี้โค้ดเต็มค่ะช่วยดูให้หน่อยได้มั้ยคะ ขอบคุณมากๆค่ะ
<?php
//check if form is submitted
if (isset($_POST['submit']))
{
include "config.php";
$name = $_POST['fname'];
$notel = $_POST['notel'];
$nmasyarikat = $_POST['nmasya'];
$nopendsya = $_POST['pendsya'];
$lokasi1=implode(' ',$_POST['lokasi']);
$skop1=implode(' ',$_POST['sk']);
$nota = $_POST['nota'];
$kmhr1=implode(' , ',$_POST['kmhr']);
$filename = $_FILES['filename']['name'];
//upload file
if($filename != '')
{
$ext = pathinfo($filename, PATHINFO_EXTENSION);
$allowed = ['pdf', 'txt', 'doc', 'docx', 'png', 'jpg', 'jpeg', 'gif', 'excel', 'mp4'];
//check if file type is valid
if (in_array($ext, $allowed))
{
// get last record id
$sql = 'select max(id) as id from information';
$query_sql = mysqli_query($link, $sql); <--- เกิดตรงนี้
if (count($query_sql) > 0)
{
$row = mysqli_fetch_array($query_sql);
$filename = ($row['id']+1) . '-' . $filename;
}
else
$filename = '1' . '-' . $filename;
//set target directory
$path = 'uploads/';
if (!is_dir($path)) {
echo 'error';
} else {
move_uploaded_file($_FILES['filename']['tmp_name'],($path . $filename));
}
// insert file details into database
$sql = "INSERT INTO information(id,name,notel,nmasyarikat,nopendsya,lokasi,skop,pekerja,kemahiran,document)
VALUES(NULL,'$name','$notel','$nmasyarikat','$nopendsya','$lokasi1','$skop1','$kmhr1','$filename')";
$query_sql=mysqli_query($link,$sql); <--- เกิดตรงนี้
if($query_sql){
//noti after submit and go to main page
echo "<script>
window.location.href='subcon.php';
alert('Matlumat anda telah disimpan. Terima Kasih');
</script>";
}
else{
echo mysqli_connect_error($link);
echo'<script>alert("Failed To Insert")</script>';
}
}
else
{
header("Location: subcon.php?st=error");
}
}
else
header("Location: subcon.php");
}
?>
Tag : PHP, MySQL, HTML, XAMPP
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| Date :
2023-03-05 09:17:35 |
By :
Ruby |
View :
843 |
Reply :
3 |
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มีแล้วนะคะ
อยู่บันทัดที่5 include "config.php";
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| Date :
2023-03-05 10:02:41 |
By :
Ruby |
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