สอบถามเกี่ยวกับPHP Upload รูปภาพลงในฐานข้อมูล MySQL (ลองทำบน host จริงติดปัญหาครับ)

        <form name="form1" method="post" action="PageUploadToMySQL2.php" enctype="multipart/form-data">
	Name : <input type="text" name="txtName"><br>
	Picture : <input type="file" name="filUpload"><br>
	<input name="btnSubmit" type="submit" value="Submit">
	</form>

<?php
	if(move_uploaded_file($_FILES["filUpload"]["tmp_name"],"myfile/".$_FILES["filUpload"]["name"]))
	{
		echo "Copy/Upload Complete<br>";

		//*** Insert Record ***//
		$objConnect = mysql_connect("localhost","mydata","********") or die("Error Connect to Database");
		$objDB = mysql_select_db("mydata");
		$strSQL = "INSERT INTO files ";
		$strSQL .="(Name,FilesName) VALUES ('".$_POST["txtName"]."','".$_FILES["filUpload"]["name"]."')";
		$objQuery = mysql_query($strSQL);		
	}
?>
<a href="PageUploadToMySQL3.php">View files</a>

<?php
	$objConnect = mysql_connect("localhost","mydata","**********") or die("Error Connect to Database");
	$objDB = mysql_select_db("mydata");
	$strSQL = "SELECT * FROM files";
	$objQuery = mysql_query($strSQL) or die ("Error Query [".$strSQL."]");
?>
<table width="340" border="1">
<tr>
<th width="50"> <div align="center">Files ID </div></th>
<th width="150"> <div align="center">Picture</div></th>
<th width="150"> <div align="center">Name</div></th>
<th width="150"> <div align="center">Edit</div></th>
</tr>
<?php
	while($objResult = mysql_fetch_array($objQuery))
	{
?>
<tr>
<td><div align="center"><?php echo $objResult["FilesID"];?></div></td>
<td><center><img src="myfile/<?php echo $objResult["FilesName"];?>"></center></td>
<td><center><?php echo $objResult["Name"];?></center></td>
<td><center><a href="PageUploadToMySQL4.php?FilesID=<?php echo $objResult["FilesID"];?>">Edit</a></center></td>
</tr>
<?php
	}
?>
</table>
<?php
mysql_close($objConnect);
?>

<?php
	$objConnect = mysql_connect("localhost","mydata","**********") or die("Error Connect to Database");
	$objDB = mysql_select_db("mydata");
	$strSQL = "SELECT * FROM files WHERE FilesID = '".$_GET["FilesID"]."' ";
	$objQuery = mysql_query($strSQL) or die ("Error Query [".$strSQL."]");
	$objResult = mysql_fetch_array($objQuery);
?>
	<form name="form1" method="post" action="PageUploadToMySQL5.php?FilesID=<?php echo $_GET["FilesID"];?>" enctype="multipart/form-data">
	Edit Picture :<br>
	Name : <input type="text" name="txtName" value="<?php echo $objResult["Name"];?>"><br>
	<img src="myfile/<?php echo $objResult["FilesName"];?>"><br>
	Picture : <input type="file" name="filUpload"><br>
	<input type="hidden" name="hdnOldFile" value="<?php echo $objResult["FilesName"];?>">
	<input name="btnSubmit" type="submit" value="Submit">
	</form>

<?php

		//*** Update Record ***//
		$objConnect = mysql_connect("localhost","mydata","**********") or die("Error Connect to Database");
		$objDB = mysql_select_db("mydata");

		$strSQL = "UPDATE files ";
		$strSQL .=" SET NAME = '".$_POST["txtName"]."' WHERE FilesID = '".$_GET["FilesID"]."' ";
		$objQuery = mysql_query($strSQL);		
	
	if($_FILES["filUpload"]["name"] != "")
	{
		if(move_uploaded_file($_FILES["filUpload"]["tmp_name"],"myfile/".$_FILES["filUpload"]["name"]))
		{

			//*** Delete Old File ***//			
			@unlink("myfile/".$_POST["hdnOldFile"]);
			
			//*** Update New File ***//
			$strSQL = "UPDATE files ";
			$strSQL .=" SET FilesName = '".$_FILES["filUpload"]["name"]."' WHERE FilesID = '".$_GET["FilesID"]."' ";
			$objQuery = mysql_query($strSQL);		

			echo "Copy/Upload Complete<br>";

		}
	}
?>
<a href="PageUploadToMySQL3.php">View files</a>